Someone please help! I asked earlier but they just stole the points... (12-15) Q(x) = 2x^4 - 7x^3 + 6x^2 + x -2
1. Use synthetic division to determine whether (x-1) is a factor of Q(x).

2. Use synthetic division in to find Q(-2)

3. List all of the possible rational roots of Q(x) = 0

4. Find all of the real roots Q(x) =0

1)

2) Q(-2) = (-2-1)².(-2-2).(2.-2+1)

= (-3)².(-4).(-3)

= 108

3) Q(x) = 0

=> (x-1)²(x-2)(2x+1) = 0

⇔ x - 1 = 0 or x - 2 = 0 or 2x +1 = 0

4) x-1 = 0 or x - 2 = 0 or 2x + 1 = 0

⇔ x = 1 or x = 2 or x = -1/2

Step-by-step explanation:

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation:

"image"

step-by-step explanation:

in most of these problems, the notation is that the point with a "prime" is the image of the point without. that is, b' is the image of b.

here, there is no dilation or reflection. there is simply translation (with no direction shown). which figure you call the "preimage" and which one you call the "image" is up to you. as a matter of convention, the naming is as described above.