Find the volume of a right circular cone that has a height of 17.6 m and a base with a radius of 8 m. Round your answer to the nearest tenth of a cubic meter.

1179m^3

Step-by-step explanation:

Given radius=8m

Height=17.6m

Volume of the cone=1/3πr^2h

1/3 πr^2h

=1/3×3.14×8×8×17.6

=1178.96

Nearest tenth is 1179

So volume is 1179m^3

g(x) = x² + 2

step-by-step explanation:

it is given that the graphs are the same shape.

the only difference is that the red graph is 2 units higher than the blue graph.

that is to say that the red graph is simply the blue graph that has been moved vertically by 2 units in the positive y direction.

hence

g(x) = f(x) + 2

or

g(x) = x² + 2

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so: