Aline has a slope of -4/5 . which ordered pairs could be points on a line that is perpendicular to this line? check all that apply.
(–2, 0) and (2, 5)
(–4, 5) and (4, –5)
(–3, 4) and (2, 0)
(1, –1) and (6, –5)
(2, –1) and (10, 9)

Step-by-step explanation:

Given that a  line has a slope of

For any line perpendicular to this line,

the slope of the line =

Let us check whether the given options satisfy this

a) (-2,0) and (2,5)... slope =

Yes true

b) (–4, 5) and (4, –5)... slope =

No not true.

c) (–3, 4) and (2, 0)

Slope =

No not true.

d) (1, –1) and (6, –5)

Slope =

No, not true.

e) (2, –1) and (10, 9)

Slope = 5/4

True.

e) (2, –1) and (10, 9)

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116