Weights of the vegetables in a field are normally distributed. From a sample Carl Cornfield determines the mean weight of a box of vegetables to be 180 oz. with a standard deviation of 8 oz. He wonders what percent of the vegetable boxes
he has grouped for sale will have a weight more than 196 oz.
Carl decides to answer the following questions about the population of vegetables from these sample statistics:
Carl calculates the Z-score corresponding to the weight 196 oz.
Using the table (column .00), Carl sees the area associated with this z-score is O.
Carl rounds this value to the nearest thousandth or 0.
Now, Carl subtracts 0.50 - 0.

english, cause i can’t you

7

step-by-step explanation:

the solution of the equation is 2.23 ⇒ answer b

step-by-step explanation:

* lets revise the meaning of exponential function

- the form of the exponential function is y = ab^x, where a ≠ 0, b > 0 ,  

  b ≠ 1, and x is any real number

- it has a constant base b

- it has a variable exponent x

- to solve an exponential equation, take the log or ln of both sides,  

  and solve for the variable

* lets solve the problem

∵

- the base is 7 and the exponent is x

- insert ㏑ in both sides

∴

- use the rule

∴ x ㏑(7) = ㏑(77)

- to find x divide both sides by ㏑(7)

∴

* the solution of the equation is 2.23 to the nearest 2 decimal places

the answer is: -22 also a

hope i

-lavira: )