What is the point-slope equation of the line that is perpendicular to the line shown and passes through (-4, -3)?

y+3= -4x

Step-by-step explanation:

general equation is (y-y1) = m(x-x1)

m=rise/run=  -4/1 (is negative because looking from left to right on the graph it goes downward)

pick any point on the line to put in. the equation for example (0,-3)

y+3= -4x

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this