Aline passes through the points (2,-4) and (6,10)

what is the equation of the line

(2,-4)(6,10)
slope(m) = (10 - (-4) / (6 - 2) = (10 + 4) / 4 = 14/4 reduces to 7/2

y = mx + b
slope(m) = 7/2
(2,-4)...x = 2 and y = -4
now we sub and find b, the y int
-4 = 7/2(2) + b
-4 = 7 + b
-4 - 7 = b
-11 = b

so ur equation is : y = 7/2x - 11