Triangle T R S has centroid Z. Lines are drawn from each point to the midpoint of the opposite side to form line segments T W, R V, and S U. In triangle TRS, VZ = 6 inches. What is RZ?

3 inches
6 inches
12 inches
18 inches

C?

Step-by-step explanation:

From eyeballing it, I can see that RZ is definetely not the first two. and RZ looks about exactly double the length of VZ. Hope this helps. :)

C. 12 inches

Step-by-step explanation:

May I have brainliest please? :)

x = 3 ± √(5+y)

answer:   the paragraph proof is mentioned below.

step-by-step explanation:

given: in a δxwy where

such that, ∠wzx ≅ ∠yzx and zw≅zy

we have to prove that: segment zx is a perpendicular bisector of segment wy.

prove: since, zw≅zy ⇒ ∠wzy is a supplementary angle.

then, ∠wzy= 180°

⇒∠wzx + ∠yzx = 180° ( because xz divides ∠wzy into two parts)

but, ∠wzx ≅ ∠yzx ( given)

⇒∠wzy+∠wzy=180° ( by substitution)

⇒2∠wzy=180°

⇒∠wzy=90°

⇒∠wzy=∠yzx =90°

therefore, xz⊥wy where wz=zy

⇒zx is a perpendicular bisector of wy.