A pumpkin is thrown out of a window that is 4 feet high with an upward velocity of 14. When will the pumpkin hit the ground?
A. 0.4 seconds
OB. 1.1 seconds
O c. 7 seconds
OD. 0.22 seconds

Step-by-step explanation:

Given

Height H = 4 feet

Velocity = 14ft/s

Required

Time the pumpkin will hit the ground

Using the equation of mottion

H = ut + 1/2gt²

4 = 14t + 1/2(9.8)t²

4 = 14t + 4.9t²

4.9t²+14t-4 = 0

t = -14±√196+16(4.9)/2(4.9)

t = -14±√196+78.4/2(4.9)

t = -14±16.57/9.8

t = -14+16.57/9.8

t = 2.57/9.8

t = 0.2seconds

use the power rule  

( a b ) n = a n b n

to distribute the exponent.

apply the product rule to  

3 x 2 y 3 . ( 3 x 2 ) 2 ( y 3 ) 2

apply the product rule to  

3 x 2 . 3 2 ( x 2 ) 2 ( y 3 ) 2

raise  

3

to the power of  

2 . 9 ( x 2 ) 2 ( y 3 ) 2 multiply the exponents in   ( x 2 ) 2

.

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 2 ⋅ 2 ( y 3 ) 2

multiply  

2   by   2 . 9 x 4 ( y 3 ) 2

multiply the exponents in  

( y 3 ) 2 .

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 4 y 3

⋅

2

multiply  

3   by   2 . 9 x 4 y 6

step-by-step explanation:

ur mom

step-by-step explanation: