What is the distance between z1 = 5 - 2i and z2 = 8 + i?

3√2
13.3
2√3
18

d=2√10

Step-by-step explanation:

The distance between the two points will be given by:

d=√[(x-x1)^2+(y-y1)^2]

point z1=(3-2i) has the coordinates of (3,-2)

point z2=(5-8i) has the coordinates of (5,-8)

thus the distance between them will be:

d=√[(-8-(-2)²+(5-3)²)]

d=√[(-6)²+2²]

d=√(36+4)

d=√40

d=2√10

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)