∫C((x2+5y)i⃗ +3y3j⃗ )⋅dr⃗ ∫ C ( ( x 2 + 5 y ) i → + 3 y 3 j → ) ⋅ d r → where C C consists of the three line segments from (3,0,0) ( 3 , 0 , 0 ) to (3,2,0) ( 3 , 2 , 0 ) to (0,2,0) ( 0 , 2 , 0 ) to (0,2,4) ( 0 , 2 , 4 ) .

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]

d. vertex

step-by-step explanation:

square root of 36/6 = 2.449489743

square root of 16/6 = 1.632993162

square root of 6 = 2.449489743

the answer is square root of 16/6 because the square root of 36/6 is the same answer as square root of 6 = 2.449489743

hi there!

question 1 answer: p/q can be terminating when q = 5^m * 2^n

question 2 answer: -1 and -1

question 3 answer: -4

question 4 answer: 5/12

hope this : )