A simple random sample of size n is drawn from a population that is normally distributed. The sample mean, x, is found to be 108, and the sample standard deviation, s, is found to be 10. (a) Construct a 96% confidence interval about μ if the sample size, n, is 17. (b) Construct a 96% confidence interval about μ if the sample size, n, is 12. (c) Construct a 90% confidence interval about μ if the sample size, n, is 17. (d) Could we have computed the confidence intervals in parts (a)-(c) if the population had not been normally distributed?

Step-by-step explanation:

A simple random sample of size n is drawn from a population that is normally distributed. The sample mean, x, is found to be 108, and the sample standard deviation, s, is found to be 10. (a) Construct a 96% confidence interval about μ if the sample size, n, is 17. (b) Construct a 96% confidence interval about μ if the sample size, n, is 12. (c) Construct a 90% confidence interval about μ if the sample size, n, is 17. (d) Could we have computed the confidence intervals in parts (a)-(c) if the population had not been normally distributed?

38.5

step-by-step explanation:

lets say, first number = r

second number = 3r+7

total = 49

(r)+(3r+7)= 49

4r+7 = 49

4r = 42

r = 42/4

r= 10.5

3r+7 = 3(10.5)+7 = 38.5

hope this

throw the computer

step-by-step explanation: