Exponential Function Characteristics Listed in the Item Bank are some key terms and expressions associated with the categories seen in the Venn Diagram. To find out more Information about
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ITEM BANK: Move to Bottom
asymptote: y = 0
increasing on (-00,00)
range: (0,00)
range: (1,00)
y-intercept: 1
y-intercept: 2
y-intercept: 3
y = 3
drag and drop there
y=3* & y = 3*+1
y=3' & y = 3^(x + 1)
All
drag and drops where
drag and drop answer here
crag and drop antece
y = 3+1
y = 3^(x + 1)
y=3* +1 & y = 3^(x + 1)
do and drophe
de do

step-by-step explanation:

i have done this all on a piece of paper but idk how to put it on here cuz it needs to be drawn

d. vertex

step-by-step explanation:

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!