Richard went kayaking last weekend. On Saturday, he kayaked for 2 hours and went 7 kilometers. On Sunday, he kayaked on a different river for 3 hours and went 12 kilometers. On which day did Richard kayak at a faster average speed?

Richard kayaked faster on Sunday

Explanation: In a situation like this, you would need to find the average speed, or the rate at which Richard was kayaking on both days. On Saturday, Richard kayaked 2 hours and went 7 kilometers, meaning you would divide 7 by 2 to get the average speed, or the rate at which Richard traveled while kayaking. On Sunday, Richard kayaked for 3 hours and traveled a total of 12 kilometers. If we did the same thing we did on Saturday, and divided 12 by 3, we would get the average speed. On Saturday, Richard kayaked at a rate of 3.5 kilometers per hour, and on Sunday, Richard kayaked at a rate of 4 kilometers per hour, meaning Richard kayaked faster on Sunday.

First subtract 10 from both side
y^2+6y-16=0
(y+8)(y-2)=0
-8 and 2