If 10g of a radioactive substance are present initially and 3 years later only 5 g remain, how much of the substance will be present in 5 years

The mass of the substance that will remain after 5 years is 3.15 g

Step-by-step explanation:

Given;

initial mass of the radioactive substance, a = 10 g

remaining mass after 3 years, y = 5g

Generating a half-life equation;

After 5 years, the mass of the substance that will be present is given by;

y = 10(0.7937)⁵

y = 3.15 g

Therefore, the mass of the substance that will remain after 5 years is 3.15 g

answer: the answer is one

step-by-step explanation:

pemdas, in this situation there is no parenthesis or exponents so you go to multiplication, 1x1=1, then division 1/1= 1 then addition 1+1=2 then subtraction 2-1=1

in if you ask questions, the points are taken from your total and given to the one who answered it..

so if i have 30 points and i ask a question for 5 points, then when someone asks a question i will lose 5 points and the answerer earns 5

happy to