Carlos observes a ship from a cliff. The ship is 1.3 km away from the bottom of the cliff. Given that the height of the cliff is 150m, find the angle of depression of
the ship.

Step-by-step explanation:

Step one:

given

The distance of the ship from the base= 1.3km

Height of the cliff= 150m= 1.5km

Step two:

Required

angle of depression

Applying SOH CAH TOA

The opposite is to the angle of depression is the height which is 1.5km

The distance of the ship from the foot of the cliff is the adjacent  which is 1.3km

Tan ∅=Opp/Adj

Tan ∅=1.5/1.3

∅=Tan-1 1.5/1.3

∅=Tan-1 1.153

∅=49.06

49° approx.

my guess would be b and d, but i didn’t actually get out the pen and paper. lol

a, b, c, d are correct.

step-by-step explanation:

we have g(x) = 3 and are required to find which option is a translation of g(x).

now, 'translation' is a transformation which means to shift the function in any direction and the general form of translation is g(x) + k, where k is any real number.

so, according to the options we see that all are correct as they satisfy the general form of translation.

also, it can be seen from the graph below that the function g(x) = 3 is shifted from its position in all the four options.