Find an equation of the line that passes through the point (2, -8) and is perpendicular to the line 2x-6y=10

9514 1404 393

  3x +y = -2

Step-by-step explanation:

First of all, it is helpful to put the given equation in standard form. We can do that by dividing it by 2 to eliminate the common factor from the numbers.

  x -3y = 5

Next, since you want the perpendicular line, you can swap the coefficients of x and y, and negate one of them. This can give you ...

  3x +y = (some constant)

The constant will be found using the given point.

  3x +y = 3(2) +(-8) = -2 . . . the perpendicular line

An equation is ...

  3x +y = -2

since the airplane is moving with constant speed then the distance travelled can be calculated by x=u*t

in km/h would be:

x=640*3.5=2.240 km

in m/s would be:

u=640 km/h= 640.000 m/h =640.000/ 3600 m/s =177.8 m/s

t= 3.5 h= 3.5 * 3600 s=12.600 s

then x=u*t= 177.8*12.600= 2.240.280 m

answer: 0

step-by-step explanation: the positive, like 5, + its opposite, like -5 would be 0

5+(-5)=0, or 5-5=0