4 consecutive integers have a sum of 22. What is the least of the 4 integers?

The least of the four integers is 4.

Step-by-step explanation:

Let x be the first integer.

x + (x + 1) + (x +2) + (x + 3) = 22

4x + 6 = 22

4x = 16

x = 4

4 + 5 + 6 + 7 = 22

let's solve your equation step-by-step.

4x+2=2x+12

step 1: subtract 2x from both sides.

4x+2−2x=2x+12−2x

2x+2=12

step 2: subtract 2 from both sides.

2x+2−2=12−2

2x=10

step 3: divide both sides by 2.

2x

2

=

10

2

x=5

step-by-step explanation: