According to a recent survey, 81 percent of adults in a certain state have graduated from high school. If 15 adults from the state are selected at random, what is the probability that 5 of them have not graduated from high school? ⁢(2015)(0.19)15(0.81)5
A

(105)(0.19)15(0.81)15
B

(105)(0.81)5(0.19)10
C

(155)(0.19)5(0.81)10
D

(155)(0.81)5(0.19)10
E

The probability that 5 of them are not graduated from the high school is:

Step-by-step explanation:

Given information:

The probability of getting adults in a certain state have graduated from high school.

Probability of success

Probability of failure

Sample (number of adults)

Now, in the binomial distribution

Let, be a random variable,

So,

Now , the probability that 5 of them have graduated from the high school

We know that :

On putting the values in the above equation we get:

Now, the probability that 5 of them are not graduated from the high school is:

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The probability that 5 of them have  graduated from high school

             = 1 - p(X=5)

            =  

Step-by-step explanation:

Step(i) :-

The probability of getting adults in a certain state have graduated from high school

Probability of success (p)  = 0.81

Probability of failure (q) = 1- p = 1 - 0.81 = 0.19

Given number of adults 'n' = 15

Step(ii):-

Let 'X' be a random variable in binomial distribution

The probability that 5 of them have  graduated from high school

we know that

=   1001

The probability that 5 of them have  graduated from high school

Step(iii):-

The probability that 5 of them have  graduated from high school

             = 1 - p(X=5)

            =  

answer: h

step-by-step explanation:

step-by-step explanation :

we know that

the measurement of the outer angle is the semi-difference of the arcs which comprises

in this problem

m< xzy is the outer angle

substitute the values

the measure of angle xoy is equal to

> by central angle

substitute the value