Catherine is at the Supermarket, and knows that she is 50 yards from her school. The map on her phone shows that the school is \large \frac{3}{4} inch from her current location. If Catherine's current location is 3 inches from home on the same map, how far is Catherine from her home? a 112.5 yards b 200 yards c 250.5 yards d 150 yards

b 200 yards

Step-by-step explanation:

Scaling

Real magnitudes can be scaled up or down to adapt to the size of a sheet of paper or the screen of a computer or phone.

Catherine knows she is 50 yards from the school and it's shown as a distance of 3/4 inch on her phone map.

We can calculate the scaling factor from the real distance to the map distance by dividing:

Now she sees that she's 3 inches from home on the same map. This is equivalent to a real distance of:

Catherine is 200 yards from her home.

b 200 yards

x coordinate can be written by using the formula, x= x1 + 2/5(x2 - x1)

step-by-step explanation:

formula

x = x1 + p/w(x2 - x1)

let the line segment ab with a(x1,y1) and b(x2,y2)

a point(x,y) divide ab in the ratio, 2: 3 the x coordinate can be written as

x = x1 + p/w(x2 - x1)

here p=2 and w = 2+3

therefore,

x coordinate can be written by using the formula, x= x1 + 2/5(x2 - x1)

similarly y coordinate y = y1 + 2/5(y2 - y1)