In a running competition, a bronze, silver and gold medal must be given to the top three girls and top three boys. If 10 boys and 8 girls are competing, how many different ways could the six medals possibly be given out?

120

Step-by-step explanation:

The number of ways the gold can be awarded is 6

The number of ways the silver can be awarded is 5

And the number of ways the bronze can be awarded is 4

6 * 5 * 4 = 120

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0