What is the angle of depression from the start of a 6-foot high access ramp that ends at a point 40 feet away along the ground? Nearest tenth of a degree.

Step-by-step explanation:

The set up will give a right angles triangle;

Given

The height of the ramp (opposite) = 6 foot

distance away along the ground = 40 feet (adjacent)

Required

Angle of depression theta

Using the TOA identity;

tan theta = opposite/adjacent

tan theta = 6/40

tan theta = 0.15

theta = tan^-1{0.15}

theta =8.53 degrees

hence the angle of depression to nearest tenth of a degree is 89.5 degrees

start with a line segment pq that we will copy. mark a point r that will be one endpoint of the new line segment. set the compasses' point on the point p of the line segment to be copied. adjust the compasses' width to the point q. the compasses' width is now equal to the length of the line segment pq.

step-by-step explanation:

ans789

step-by-step explanation: