Find the exact value of 0 tan165 using the appropriate identity formula. Rationalize denominator if needed.

Step-by-step explanation:

Given;

tan165⁰

165⁰ is in the second quadrant, and sine is positive in this quadrant, thus tan will be negative.

In second quadrant, tanθ = -tan(180 - θ)

tan165⁰ = -tan(180-165)

tan165⁰ = -tan15⁰

Therefore,

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)

step-by-step explanation: 2