In a survey of 468 registered voters, 152 of them wished to see Mayor Waffleskate lose her next election. The Waffleskate campaign claims that no more than 32% of registered voters wish to see her defeated. Does the 95% confidence interval for the proportion support this claim? a. The reasonableness of the claim cannot be determined.
b. Yes
c. No

b. Yes

Step-by-step explanation: Confidence Interval for a population proportion is calculated as:

p ±

where

p is the sample proportion

n is sample size

z is z-score, in this case, as it is 95%, z-score=1.96

Calculating confidence interval:

p = 0.3248

0.3248 ±

0.3248 ±

0.3248 ± 0.0425

Interval: 0.2823 < μ < 0.3673

The interval means we are 95% sure the true mean is between 0.2823 and 0.3673. As the campaign claims a proportion of no more than 0.32 of the voters wants to see Mayor Waffleskate defeated and the number is in the confidence interval, the claim is supported.

i use my brain for prombles like this maybe you could try it

step-by-step explanation:

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )