Ryan is choosing between two exercise routines. In Routine #1, he burns 22 calories walking. He then runs at a rate that burns 10.5 calories per minute. In Routine #2, he burns 39 calories walking. He then runs at a rate that burns 6.25 calories per minute.

Complete question :

Ryan is choosing between two exercise routines. In Routine #1, he burns 22 calories walking. He then runs at a rate that burns 10.5 calories per minute. In Routine #2, he burns 39 calories walking. He then runs at a rate that burns 6.25 calories per minute. For what amounts of time spent running will Routine #1 burn at most as many calories as Routine #2?

4 minutes

Step-by-step explanation:

Given the following exercise routines :

Routine #1,

Walking : burns 22 calories walking. He then running : burns 10.5 calories per minute.

Routine #2,

Walking : burns 39 calories walking. He then running : burns 6.25 calories per minute.

Let number of tone spent running = t

Hence,

Routine 1 ; calories burned

22 + 10.5t

Routine 2 ; calories burned

39 + 6.25t

Equating the two equations :

22 + 10.5t = 39 + 6.25t

10.5t - 6.25t = 39 - 22

4.25t = 17

t = 17/4.25

t = 4

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2

i do not know the answer

step-by-step explanation: