Taking into account identical letters, how many ways can the researcher arrange the word CALLITRICHIDAE that start or end with vowels?

241,920 different ways

Step-by-step explanation:

We have 6 vowels, but A repeats twice and I repeats three times, so the number of ways in which each can either start or end the word:

³P₂ = 3! / (3 - 2)! = 6 / 1 = 6 ways

You can start words with A, E or I, or end the words with A, E, or I.

the remaining 8 consonants can be arranged in 8! ways = 40,320 ways

total number of ways that the letters can be arranged = 6 x 40,320 = 241,920 different ways

30 units^2

step-by-step explanation:

area is l × w

the length is 3

and the width is 10

3 × 10= 30 units squared

1.true 2.false? ? i think. .

step-by-step explanation: