The stopping distance (s) of a truck varies directly as the square of its speed (v). If a truck travelling at 50 mph requires 200 feet to stop, find the stopping distance for a truck travelling at 65 mph.

The distance is 338ft

Step-by-step explanation:

Given

Represent distance with s and velocity with v:

When

Required

Determine the distance when velocity is 65mph

From the question, we understand that:

Convert to equation

Substitute 200 for s and 50 for v

Make k the subject:

To get s when v = 65.

Substitute 65 for v and 2/25 for k in

Hence, the distance is 338ft

slope is 35 and 20 miles is the y-intercept.

step-by-step explanation: