We want to solve the following system of equations using the substitution method. Equation 1 3x-2y=-6
Equation 2 y=-5x-3

First find X by substitution of the variable Y.
step by step answer please

In the second equation you are given what Y equals, which is (-5x - 3). You would use this equation and plug it into the y value given in the first equation where it says 2y and solve

That would be

3x - 2(-5x - 3) = -6
3x + 10x + 6 = -6
3x + 10x = -6 - 6
13x = -12
X = -12/13

Then if you want to solve for Y you can use any equation and plug in the x-value found.

I’m going to use equation 2.

Y = -5x - 3
Y = -5(-12/13) - 3
Y = 4.615 - 3
Y = 1.615

(-12/13, 1.615)

Therefore the x-value is -12/13 and the y-value is 1.615.

A= b/2 because u simplying both sides of equation