How many diagonals can be constructed from one vertex of an n-gon? State your answer in terms of n and, of course, justify your answer.

Polygon Diagonals. The number of diagonals in a polygon = n(n-3)/2, where n is the number of polygon sides. For a convex n-sided polygon, there are n vertices, and from each vertex you can draw n-3 diagonals, so the total number of diagonals that can be drawn is n(n-3).

what is the graph

step-by-step explanation:

41*67/2=1373.5

step-by-step explanation:

i just used a calculator