Josie recorded the average monthly temperatures for two cities in the state where she lives. For City 1, what is the mean of the average monthly temperatures? What is the mean absolute deviation of the average monthly temperatures? Round your answers to the nearest tenth. Average Monthly Temperatures for City 1 (° F)
70, 49, 56, 57, 25, 59, 35, 71, 57, 73, 28, 78

Average Monthly Temperatures for City 2 (° F)
55, 34, 41, 42, 10, 44, 20, 56, 42, 58, 13, 63

The mean average monthly temperature in City 1 is
54.8
°F.
The mean absolute deviation for the average monthly temperature in City 1 is
°F.

I wants points lol

Step-by-step explanation:

Sorry

rick has $1400 and sally has $1500

step-by-step explanation:

to find amount of money rick has after 10 years :

principal = $1000 , time = 10 years , rate = 4% annually

to find amount of money sally has after 10 years :

her friend gives to pay her $50 per year, therefore money she has after 10 years = 50 × 10 = $500

also, sally gets $1000 after 10 years,

therefore, total amount of money sally has after 10 years = 500 + 1000 = $1500

so, after 10 years : rick has $1400 and sally has $1500

0 and 5 minutes

step-by-step explanation:

given that one morning eight buses arrive late by the number of minutes given below:

0 8 2 6 9 2 0 7 8

write these in ascending order

0   0 2 6 7 8 8 9

in the afternoon two more buses arrive at the bus stop say by x and y minutes late.

total number of buses = 10

median = average of 4th and 5th after arranging in ascending order

since 4th entry is 6, the values of x and y should be below 6

also given 0 is the mode so either x or y or both should be 0 because then only 0 gets the maximum frequency and hence mode

thus we have

0 0 0 2 6 7 8 8 9 and another unknown entry which is below 6.

since median is 3.5, we have the unknown entry to be 5 only because then only median =( 2+5)/2

thus the after noon buses were late by 0 and 5 minutes.