In the standard xy coordinate plane, what are the coordinates of the midpoint of a line segment whose endpoints are (-3, 0) and (7, 4)? A(2, 2)

B(5, 4)

C(5, 2)

D(2, 4)

(2, 2)

Step-by-step explanation:

|-3|+|7|=10

10÷2=5

7-5=2

(2, y)

|0|+|4|=4

4÷2=2

4-2=2

(2, 2)

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.