If m3 = 54º, find each measure. a. m1 =
1. m27 =
k. 212
12
13
b. m2 =
g. 28 =
I.
m213
14
c. m2 4 =
h. m29 =
mm214 =
9
10
d. m.25 =
1. M210 =
e. m26 =
j. 7211 =

$4034.40

the perimeter of the field is the sum of the lengths of the four sides:

47 yd + 158 yd + 47 yd + 158 yd = 410 yd

the cost of 3 ft (1 yd) of fence is 3×$3.28 = $9.84.

so the cost of jake's wood perimeter fance is

(410 yd) × ($9.84 /yd) = $4034.40

t hope this

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