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Mathematics, 18.11.2020 01:40 niescarlosj

The center of mass of quarter circle given by y=sqrt(r2βˆ’x2) ,x ∈ [0,r] is the point P=( , )
Hint: Use symmetry.

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The center of mass of quarter circle given by y=sqrt(r2βˆ’x2) ,x ∈ [0,r] is the point P=( , )
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