The half-life of a certain radioactive substance is 45 days. There are 6.2 grams present initially. On what day will there be less than 1 gram remaining? Day

There will be less than 1 gram of the radioactive substance remaining by the elapsing of 118 days

Step-by-step explanation:

The given parameters are;

The half life of the radioactive substance = 45 days

The mass of the substance initially present = 6.2 grams

The expression for evaluating the half life is given as follows;

Where;

N(t) = The amount of the substance left after a given time period = 1 gram

N₀ = The initial amount of the radioactive substance = 6.2 grams

= The half life of the radioactive substance = 45 days

Substituting the values gives;

The time that it takes for the mass of the radioactive substance to remain 1 g ≈ 118.45 days

Therefore, there will be less than 1 gram of the radioactive substance remaining by the elapsing of 118 days.

so what is the problem what are they asking you to solve

step-by-step explanation:

so what is the problem what are they asking you to solve