What is the value of x in the following equation?
4r +6
+ 3 = -6
-6
-3

x = -6

Step-by-step explanation:

Solve for x:

(4 x + 6)/2 + 3 = -6

Hint: | Put the fractions in (4 x + 6)/2 + 3 over a common denominator.

Put each term in (4 x + 6)/2 + 3 over the common denominator 2: (4 x + 6)/2 + 3 = 6/2 + (4 x + 6)/2:

6/2 + (4 x + 6)/2 = -6

Hint: | Combine 6/2 + (4 x + 6)/2 into a single fraction.

6/2 + (4 x + 6)/2 = ((4 x + 6) + 6)/2:

(4 x + 6 + 6)/2 = -6

Hint: | Add the numbers in 4 x + 6 + 6 together.

Add like terms. 6 + 6 = 12:

(4 x + 12)/2 = -6

Hint: | Multiply both sides by a constant to simplify the equation.

Multiply both sides of (4 x + 12)/2 = -6 by 2:

(2 (4 x + 12))/2 = -6×2

Hint: | Cancel common terms in the numerator and denominator of (2 (4 x + 12))/2.

(2 (4 x + 12))/2 = 2/2×(4 x + 12) = 4 x + 12:

4 x + 12 = -6×2

Hint: | Multiply 2 and -6 together.

2 (-6) = -12:

4 x + 12 = -12

Hint: | Isolate terms with x to the left hand side.

Subtract 12 from both sides:

4 x + (12 - 12) = -12 - 12

Hint: | Look for the difference of two identical terms.

12 - 12 = 0:

4 x = -12 - 12

Hint: | Evaluate -12 - 12.

-12 - 12 = -24:

4 x = -24

Hint: | Divide both sides by a constant to simplify the equation.

Divide both sides of 4 x = -24 by 4:

(4 x)/4 = (-24)/4

Hint: | Any nonzero number divided by itself is one.

4/4 = 1:

x = (-24)/4

Hint: | Reduce (-24)/4 to lowest terms. Start by finding the GCD of -24 and 4.

The gcd of -24 and 4 is 4, so (-24)/4 = (4 (-6))/(4×1) = 4/4×-6 = -6:

x = -6

step-by-step explanation: h: (- 3, 6)

m: (1, - 2)

o: (7, 6)

r: (- 9, - 2)

midpoint of hm: (- 1, 2)

midpoint of or: (- 1, 2)

therefore, b is the midpoint of both diagonals bisect each other !

to prove the diagonals are perpendicular, show that the product of the slopes = - 1