What are the solutions to the quadratic equation below? X^2-8x+16

x=4*

Step-by-step explanation:

*THIS IS ASSUMING THAT THIS EQUATION IS EQUAL TO ZERO

X^2-8x+16=0

Let's solve this equation by factoring. First, we need to find factors of 16 that add to -8. We find that those factors are -4 and -4. X^2 is simply x times x.

Therefore, when it is factored It should look like this:

(x-4)(x-4)=0

Now we take both factors and set them equal to zero:

x-4=0; x-4=0

In both of these equations we just need to add 4 to both sides.

x=4; x=4

x=4

HTH :)

the barter