Use the diagram shown. Which is a needed step to prove that △ABF≅△EDG?
∠BCD≅∠BCD

△CFG is isosceles.

line GF≅line GF

∠BCG≅∠DCF

This can be determined by property of congruency. Hence, option i.e. ΔCFG is an isosceles triangle is most appropriate.

Given :

From figure ΔABF and ΔEDG  are congruence by SSS property.

Proof:

From ΔABF and ΔEDG in figure,

Conditions for ΔABF and ΔEDG by SSS property of congruence,

1). AB ≅ DE [Given]

   (BC + CF) = (DC + CG)

2). BF≅DG

     CF = CG [Given → BC = CD]

3). FA ≅ EG

     (AG + GF) ≅ (EF + GF)

    AG ≅ EF

Therefore, two sides of ΔCFG are equal in measure.

Thus,ΔCFG is an isosceles triangle.

Hence, option i.e. ΔCFG is an isosceles triangle is most appropriate.

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ΔCFG is an isosceles triangle.

Step-by-step explanation:

From the picture attached,

From ΔABF and ΔEDG,

Conditions for ΔABF and ΔEDG by SSS property of congruence,

1). AB ≅ DE [Given]

2). (BC + CF) = (DF + CG)

CF = CG [Given → BC = DF]

3). FA ≅ EG

(AG + GF) ≅ (EF + GF)

AG ≅ EF

Since, two sides of ΔCFG are equal in measure

ΔCFG is an isosceles triangle.

3

step-by-step explanation:

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step-by-step explanation: