As a plane takes off it ascends at a 20 degree angle of elevation. If the plane has been traveling at an average rate of 290 ft/s and continues to ascend at the same angle, then how high is the plane after 10 seconds (the plane has traveled 2900ft).

Given :

As a plane takes off it ascends at a 20 degree angle of elevation.

If the plane has been travelling at an average rate of 290 ft/s and continues to ascend at the same angle.

To Find :

How high is the plane after 10 seconds.

Solution :

Distance travelled by plane, D = 2900 ft.

Angle of elevation, Ф = 20°.

Height gained is given by :

H = 2900 × sin 20°

H = 991.86 ft.

Therefore, height of plane after 10 seconds is 991.86 ft.

Hence, this is the required solution.

dude   i don't even know. i've been trying for hours.

step-by-step explanation:

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)