Mel spent $47.97 on three cds. Two of the cds were the same price, and the third cd cost $5.00 more than one of the other two cds. The total cost can be represented by the equation 2c + (c+5) = 43.97, where c is the cost of one lower-priced cd. What was the cost of the higher priced cd?

Given :

The total cost can be represented by the equation 2c + (c+5) = 43.97, where c is the cost of one lower-priced cd.

To Find :

The cost of the higher priced cd.

Solution :

Solving given equation :

2c + c + 5 = 43.97

3c + 5 = 43.97

3c = 43.97 - 5

3c = 38.97

c = $12.99

Therefore, cost of higher priced cd is $( 12.99 + 5 ) = $17.99 .

Hence, this is the required solution.

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