Given that the two parallel lines are cut by a transversal, and the measure of angle 2 is 50 degrees. Find each of the missing angles.

From the given diagram

angle 1= 130 degrees

Angle 3 = 130 degree

Angle 5= 50 degree

Angle 6= 130 degree

Given :

the two parallel lines are cut by a transversal

Angle 1  and angle 2  are linear pair of angles

Sum of angle 1  and angle 2 is 180

Angle 1  and angle 3 are vertical opposite angles

They are equal

When two parallel lines are cut by transversal , corresponding angles are equal

<5= <2

<5=50

Alternate exterior angles are congruent

<6=<1

<6=130

angle 1= 130 degrees

Angle 3 = 130 degree

Angle 5= 50 degree

Angle 6= 130 degree

Learn more :  link

Step-by-step explanation:

Lines m and l are the parallel lines and a line 'n' is a transverse intersecting these lines.

m∠2 = 50°

m∠1 + m∠2 = 180° [Linear pair of angles]

m∠1 = 180° - 50°

m∠1 = 130°

m∠3 = m∠1 = 130° [Vertically opposite angles]

m∠3 + m∠5 = 180° [Consecutive interior angles]

m∠5 = 180° - m∠3

        = 180° - 130°

        = 50°

m∠6 + m∠5 = 180° [Linear pair of angles]

m∠6 = 180° - 50° = 130°

its adding 5.5 each time

step-by-step explanation: