the second of the three is 6 times the first. the third is 6 less than the first. the sum of the second and third numbers is 98. find all three numbers.

83

Step-by-step explanation:

x + y + z = 83

(y + 7) + y + 2y = 83

4y + 7 = 83

4y = 76

y = 19

The second number is 19. The first is 19 + 7 or 26, and the third is 2 times 19 or 38.

A check reveals that 26 + 19 + 38 = 83

first number=14.9,second number=89.4 and third number=8.9

Step-by-step explanation:

let the first number be "a" , second number be "b" and third number be "c"

From the question above we know,

b=6a

c=a-6

And b+c=98  

so we can write,

b+c=98  

(6a)+(a-6)=98  

6a+a=98+6

7a=104

a=104/7

∴a=14.9(correct to 3 sig. fig.)

again

b=6a=6(14.9)= 89.4(correct to 3 sig. fig.)

c=a-6=(14.9)-6=8.9(correct to 3 sig. fig.)

Now if u want to make sure that ur answer is correct just add b+c and see if its 98

b+c=98

89.4+8.9=98.3=98(correct to whole number)

d

step-by-step explanation:

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.