Plss help get them 12

J' is (-8, 12) and it is on the 2nd quadrant

Step-by-step explanation:

Let us revise the cases of reflection

Let us use these rules to solve the question

∵ The point J is (-8, -12) is reflected over the x-axis

∵ The x-coordinate and the y-coordinate are negative

∴ J is on the 3rd quadrant

→ By using the first rule above

∵ The rule of reflection is rx-axis (x, y) → (x, -y)

∴ The sign of y-coordinate of the point J must be opposite

∵ The y-coordinate of the point J = -12

∴ The y-coordinate of the point J' must be 12

∴ The coordinates of point J' are (-8, 12)

∵ The x coordinate is negative and the y-coordinate is positive

∴ J' is on the 2nd quadrant

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !