A 28-foot ladder is placed against a building and the top of the ladder makes a 27° angle with the building. How far away from the building is the base of the ladder? Write only the number rounded
to the nearest tenth of a foot.

Step-by-step explanation:

The set up is a right angles triangle

Given

The length of the ladder = 28 foot (hypoenuse)

theta = angle of elevation = 27 degrees

Required

Distance of the building from the base of the ladder (Adjacent)

According to CAH;

cos theta = adj/hyp

cos 27 = adj/28

adj = 28cos27

adj = 24.95 foot

Hence the length of the building from the base of the ladder is 24.95 feet

distance covered by pamela in 9 l of fuel = 99km

let us apply unitary method here.

distance covered by pamela in 1 l of fuel =99/9 =11 km

now let us find distance covered by pamela if she has 12 l of fuel.

distance covered in 12 l = distance covered in 1 l of fuel * 12

we know that distance covered by here in 1 l is 11 km.

so distance covered in 12 l of fuel = 11*12 = 132 km.

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step-by-step explanation: