This hydraulic system should produce an output force of 50,000 newtons. How large an area should the output piston have?

Complete question is;

In a hydraulic system, a 100-newton force is applied to a small piston with an area of 0.0020 m².

This hydraulic system should produce an output force of 50,000 newtons. How large an area should the output piston have?

A2 = 1 m²

Step-by-step explanation:

Using Pascal's Law which is here applied to mechanical advantage of a hydraulic piston, we can find the area of the large piston from;

F1/A1 = F2/A2

We are given;

Force of small piston: F1 = 100 N

Area of small piston; A1 = 0.0020 m²

Force of small piston: F2 = 50000 N

Thus;

Making A2 the subject, we have;

A2 = (F2/F1)A1

A2 = (50000/100) × 0.0020

A2 = 1 m²

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step-by-step explanation: