Use the given values of n and p to find the minimum usual value n-2o and the maximum usual value n+2o. Round your answer to the nearest hundredths unless otherwise noted. n= 108, p= 0.24

A. Minimum: -13.48; maximum:65.32

B. Minimum: 34.8; maximum:17.04

C. Minimum: 21.48; maximum:30.36

D. Minimum:17.04; maximum:34.8

idk man good luck man

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;

sorry man i accidentally pressed yes my bad

step-by-step explanation: