A shopper bought 6 shirts and 8 hats for $700. A week later, at the same prices, he bought 9 shirts and 6 hats for $660. What was the cost of one shirt?

Cost of one shirt = $ 30

Step-by-step explanation:

Let cost of 1 shirt = s

Cost of 1 hat  = h

A shopper bought 6 shirts and 8 hats for $700.

6s + 8h = 700      (I)

A shopper bought 9 shirts and 6 hats for $660

9s + 6h = 660    (II)

Multiply equation (I) with 9 and multiply equation (II) with (-6) and then add. SO, now 's' will be eliminated and we can find the value of 'h'

(I) * 9                54s + 72h  = 6300

(II)*(-6)            -54s  - 36h = - 3960   {Now add}

                                 36h = 2340

                                     h = 2340/36

                                     h = 65

Cost of one hat  =  $ 65

Substitute h = 65 in equation (I)

6s + 8 * 65 = 700

6s  + 520   = 700

            6s = 700 - 520

            6s = 180

               s = 180/6

               s = 30

Cost of one shirt = $ 30

step-by-step explanation:

x^2 -12x + 36 + y^2 = 36

x^2 + y^2 = 12x

r^2 = 12rcos(theta)

r = 12 cos(theta)

care to share were the trapezoid shown is ?