110 meters of fencing are used to fence a rectangular pasture of 750 square meters of farmland. If the length of the pasture is longer than the width, what is the width of the pasture in meters?

Step-by-step explanation:

Perimeter of the rectangular pasture P = 2(L+W)

Area A = LW

L is the length

W is the width

Given

Perimeter = 110m

Area = 750m

If the length of the pasture is 40m longer than the width, then L = W+40

110 = 2L+2w

55 = L+W 1

750 = LW2

Solving simultaneously

from 1; L = 55-W

substitute into 2;

750 = (55-W)W

750 = 55W-W²

-W²+55W -750 = 0

W²-55W+750 = 0

(W²-25W)-(30W+750) = 0

W(W-25)-30(W-25) = 0

(W-25)(W-30) = 0

W-25 = 0 and W-30 = 0

w = 25m and 30m

Since L = 55-W

L = 55-25 = 30m and;

L = 55-30 = 25m

Since we are told that length id longer than the width then, the width we are going to use is 25m

x=17

step-by-step explanation:

solve 3x-24=x+10

then that makes it 2x=34 because you subtract an x from both sides to get rid of the one on the right, and then you add 24 to both sides to get rid of the 24 on the left

divide by both sides by 2 to get your answer so that you can get your answer

the answers are in the images, i received 100% on this assignment. hope this !