All I need are four equations of parallel lines

questions

1) through: (2, 3), parallel to y = 4x - 1

2) through: (5, -4), parallel to y = -

3/5x +1

3)through: (1, 2), parallel to y = 6x + 3                                                        

4)through: (-1, -1), parallel to y = -4x + 1

answers=

1)y = 4x - 5

2)y = - 3/5-1

3) y = 6x - 4

4)y = -4x - 5

1.3

step-by-step explanation:

3x2=6   9x+6

bring down the 6 on both sides

6+6=12

12= 9x

divide by 9

12/9 =

1.3 =x

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)