Which equation has a center at (2, 1) and a point on the circle of (2, -3)? O (x + 2)2 + (y + 1)2 = 16
O x - 2)2 + (y - 1)2 = 4
O(x - 2)2 + (y - 1)2 = 16
O (x + 2)2 + (y + 1)2 = 4

Option 3: is the correct answer

Step-by-step explanation:

We will find the equation of the circle with given information and then compare with the choices given.

Given

Center = (h,k) = (2,1)

And point on circle = (2,-3)

The equation of circle is given as:

The distance between center and point on circle is the radius. So using the distance formula:

Putting the values in equation of circle

Hence,

Option 3: is the correct answer