Draw two isosceles triangles, ∆ABC and ∆ADC with common base AC . Vertexes B and D are in the opposite semi-planes determined by AC . Draw the line segment BD . Prove: AC ⊥ BD

Statement Reason

∆ABC and ∆ADC are isosceles Given

Segment AC is a common base

to ∆ABC and ∆ADC Given

Let K be the midpoint of the base

of segment AC, then BK is the

perpendicular bisector of segment perpendicular bisector of isosceles AC. triangle property.

Also, DK is the perpendicular

bisector of segment AC. perpendicular bisector of isosceles

triangle property

if you are saying purchasing 3 social media ads and one newspaper ad counts as one purchase then there are:

6 purchases

if you are asking how many of each then:

18 social media ads

6 newspaper ads

for this case we have by definition, if two lines are perpendicular, then the product of their slopes is -1.

then, given the following line:

so,

we are looking for m_ {2}:

then, the line is given by:

we find "b" replacing the given point:

finally, the equation is:

option c