The equation is: y = -32 +2 Select all of the equations that would be perpendicular to this line.
y = -31 - 2
y = 2x - 5
y = {2 – 3
y = 12 +7
y = -32 +1
y=i<+3.63917
y = –2 – 3
y = -4.1 - 32

y =   x - 3 ⇒ 3rd answer

y =   x + 7 ⇒ 4th answer

y =   x + 3.63917 ⇒ 6th answer

y =   x ⇒ 8th answer

Step-by-step explanation:

The product of the slopes of the perpendicular lines is -1

The form of the linear equation is y = m x + b, where

∵ The equation of the given line is y = -3x + 2

→ Compare it with the form of the equation above

∴ m = -3

→ To find the slope of the perpendicular line to it reciprocal it and

    change its sign

∴ The slope of the perpendicular line to it is =

→ Choose all the equations that have m =

∴ y =   x - 3 ⇒ 3rd answer

∴ y =   x + 7 ⇒ 4th answer

∴ y =   x + 3.63917 ⇒ 6th answer

∴ y =   x ⇒ 8th answer

1. sometimes

2. never true

3. sometimes

step-by-step explanation:

these are pretty self explanatory if you know what supp right and com angles are

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation: